Passing a std::complex<float> constant to a function that takes a std::complex<double> argument receives the wrong real part inside the function. Passing a std::complex variable produces the expected result. Changing the function to accept a value rather than a const reference makes no difference.
#include <complex>
#include <iostream>
void f(const std::complex<double> &val) // or void f(std::complex<double> val)
{
std::cout << "In f1, val = "<< val << std::endl;
}
int main()
{
f(std::complex<float>(1,2)); // Fails
std::complex<float> b(1,2);
f(b); // Works
return 0;
}Produces the output:
In f1, val = (2,2)
In f1, val = (1,2)
This is with the Intel compiler 19.0.4.243. GCC and clang give the expected results.